F(-x)=-3x^2+2x+5

Solution for F(-x)=-3x^2+2x+5 equation:

(-F)=-3F^2+2F+5

We move all terms to the left:

(-F)-(-3F^2+2F+5)=0

We add all the numbers together, and all the variables

-(-3F^2+2F+5)+(-1F)=0

We get rid of parentheses

3F^2-2F-1F-5=0

We add all the numbers together, and all the variables

3F^2-3F-5=0

a = 3; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·3·(-5)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{69}}{2*3}=\frac{3-\sqrt{69}}{6}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{69}}{2*3}=\frac{3+\sqrt{69}}{6}
$